On Sat, Aug 16, 2014 at 11:53:18AM -0500, Wolfram Sang wrote:

quoted

+	mac_addr[5] = (macid_lo >> 8) & 0xff;
+	mac_addr[4] = macid_lo & 0xff;
+	mac_addr[3] = (macid_hi >> 24) & 0xff;
+	mac_addr[2] = (macid_hi >> 16) & 0xff;
+	mac_addr[1] = (macid_hi >> 8) & 0xff;
+	mac_addr[0] = macid_hi & 0xff;

That looks twisted, but I assume that you tested it is correct.

The registers are twisted that way.

Best regards,

Markus

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