+   - big-endian : If this property is absent, the native endian mode will
+                 be in use as default, or the big endian mode will be in use
+                 for all the device registers.

Native endian is meaningless. If a CPU supports both BE and LE, there is
no native endianness. The endianness of the kernel is dynamic while the
endianness of registers in HW is fixed. 

Just choose an endianness to assume by default (presumably little). That
way this describes the HW and always works with a kernel of arbitrary
endianness.

Thanks,
Mark.
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