Re: [PATCH v3 2/2] crypto: lrw - Do not use auxiliary buffer
From: Ondrej Mosnacek <omosnace@redhat.com>
Date: 2018-09-12 07:57:57
Also in:
dm-devel
On Wed, Sep 12, 2018 at 8:51 AM Eric Biggers [off-list ref] wrote:
On Tue, Sep 11, 2018 at 09:42:39AM +0200, Ondrej Mosnacek wrote:quoted
This patch simplifies the LRW template to recompute the LRW tweaks from scratch in the second pass and thus also removes the need to allocate a dynamic buffer using kmalloc(). As discussed at [1], the use of kmalloc causes deadlocks with dm-crypt. PERFORMANCE MEASUREMENTS (x86_64) Performed using: https://gitlab.com/omos/linux-crypto-bench Crypto driver used: lrw(ecb-aes-aesni) The results show that the new code has about the same performance as the old code. For 512-byte message it seems to be even slightly faster, but that might be just noise. Before: ALGORITHM KEY (b) DATA (B) TIME ENC (ns) TIME DEC (ns) lrw(aes) 256 64 200 203 lrw(aes) 320 64 202 204 lrw(aes) 384 64 204 205 lrw(aes) 256 512 415 415 lrw(aes) 320 512 432 440 lrw(aes) 384 512 449 451 lrw(aes) 256 4096 1838 1995 lrw(aes) 320 4096 2123 1980 lrw(aes) 384 4096 2100 2119 lrw(aes) 256 16384 7183 6954 lrw(aes) 320 16384 7844 7631 lrw(aes) 384 16384 8256 8126 lrw(aes) 256 32768 14772 14484 lrw(aes) 320 32768 15281 15431 lrw(aes) 384 32768 16469 16293 After: ALGORITHM KEY (b) DATA (B) TIME ENC (ns) TIME DEC (ns) lrw(aes) 256 64 197 196 lrw(aes) 320 64 200 197 lrw(aes) 384 64 203 199 lrw(aes) 256 512 385 380 lrw(aes) 320 512 401 395 lrw(aes) 384 512 415 415 lrw(aes) 256 4096 1869 1846 lrw(aes) 320 4096 2080 1981 lrw(aes) 384 4096 2160 2109 lrw(aes) 256 16384 7077 7127 lrw(aes) 320 16384 7807 7766 lrw(aes) 384 16384 8108 8357 lrw(aes) 256 32768 14111 14454 lrw(aes) 320 32768 15268 15082 lrw(aes) 384 32768 16581 16250 [1] https://lkml.org/lkml/2018/8/23/1315 Signed-off-by: Ondrej Mosnacek <omosnace@redhat.com> --- crypto/lrw.c | 280 ++++++++++----------------------------------------- 1 file changed, 51 insertions(+), 229 deletions(-)diff --git a/crypto/lrw.c b/crypto/lrw.c index b4f30b6f16d6..d5d2fba9af59 100644 --- a/crypto/lrw.c +++ b/crypto/lrw.c@@ -29,8 +29,6 @@ #include <crypto/b128ops.h> #include <crypto/gf128mul.h> -#define LRW_BUFFER_SIZE 128u - #define LRW_BLOCK_SIZE 16 struct priv {@@ -56,19 +54,7 @@ struct priv { }; struct rctx { - be128 buf[LRW_BUFFER_SIZE / sizeof(be128)]; - - be128 t; - - be128 *ext; - - struct scatterlist srcbuf[2]; - struct scatterlist dstbuf[2]; - struct scatterlist *src; - struct scatterlist *dst; - - unsigned int left; - + be128 t, orig_iv; struct skcipher_request subreq; };@@ -135,86 +121,31 @@ static int next_index(u32 *counter) return res; } -static int post_crypt(struct skcipher_request *req) +/* + * We compute the tweak masks twice (both before and after the ECB encryption or + * decryption) to avoid having to allocate a temporary buffer and/or make + * mutliple calls to the 'ecb(..)' instance, which usually would be slower than + * just doing the gf128mul_x_ble() calls again. + */next_index(), not gf128mul_x_ble().
Fixed for next revision, thanks.
quoted
+static void init_crypt(struct skcipher_request *req) { + struct priv *ctx = crypto_skcipher_ctx(crypto_skcipher_reqtfm(req)); struct rctx *rctx = skcipher_request_ctx(req); - struct skcipher_request *subreq; + struct skcipher_request *subreq = &rctx->subreq; - subreq = &rctx->subreq; - - while (!err && rctx->left) { - err = pre_crypt(req) ?: - crypto_skcipher_decrypt(subreq) ?: - post_crypt(req); + skcipher_request_set_tfm(subreq, ctx->child); + skcipher_request_set_callback(subreq, req->base.flags, crypt_done, req); + skcipher_request_set_crypt(subreq, req->dst, req->dst, + req->cryptlen, &rctx->orig_iv);Can you leave a comment that the 'iv' of 'subreq' is set to 'orig_iv' is set so that it's available in xor_tweak_post()? My first thought was that the 'iv' should be NULL as this same request is also used for the ECB step. Or alternatively, you could get the IV directly from 'rctx->orig_iv' in xor_tweak(), and only save the incremented IV back to 'walk.iv' on the first pass. Then subreq->iv would be left NULL.
Good point, now that we have the explicit first/second pass distinction this should be quite easy to do and will be also cleaner. Thanks, -- Ondrej Mosnacek <omosnace at redhat dot com> Associate Software Engineer, Security Technologies Red Hat, Inc.