Thread (7 messages) 7 messages, 3 authors, 2011-03-18

Re: [PATCH] Btrfs: check items for correctness as we search V3

From: Andrey Kuzmin <hidden>
Date: 2011-03-17 19:12:32

On Thu, Mar 17, 2011 at 9:18 PM, Josef Bacik [off-list ref] wrote:
Currently if we have corrupted items things will blow up in spectacul=
ar ways.
So as we read in blocks and they are leaves, check the entire leaf to=
 make sure
all of the items are correct and point to valid parts in the leaf for=
 the item
data the are responsible for. =C2=A0If the item is corrupt we will ki=
ck back EIO and
not read any of the copies since they are likely to not be correct ei=
ther. =C2=A0This
will catch generic corruptions, it will be up to the individual calle=
rs of
quoted hunk ↗ jump to hunk
btrfs_search_slot to make sure their items are right. =C2=A0Thanks,
diff --git a/fs/btrfs/disk-io.c b/fs/btrfs/disk-io.c
index 495b1ac..9f31e11 100644
--- a/fs/btrfs/disk-io.c
+++ b/fs/btrfs/disk-io.c
@@ -323,6 +323,7 @@ static int btree_read_extent_buffer_pages(struct =
btrfs_root *root,
=C2=A0 =C2=A0 =C2=A0 =C2=A0int num_copies =3D 0;
=C2=A0 =C2=A0 =C2=A0 =C2=A0int mirror_num =3D 0;

+ =C2=A0 =C2=A0 =C2=A0 clear_bit(EXTENT_BUFFER_CORRUPT, &eb->bflags);
=C2=A0 =C2=A0 =C2=A0 =C2=A0io_tree =3D &BTRFS_I(root->fs_info->btree_=
inode)->io_tree;
=C2=A0 =C2=A0 =C2=A0 =C2=A0while (1) {
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0ret =3D read_e=
xtent_buffer_pages(io_tree, eb, start, 1,
quoted hunk ↗ jump to hunk
@@ -331,6 +332,14 @@ static int btree_read_extent_buffer_pages(struct=
 btrfs_root *root,
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0=
!verify_parent_transid(io_tree, eb, parent_transid))
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0=
 =C2=A0 =C2=A0return ret;
+ =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 /*
+ =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0* This buffe=
r's crc is fine, but its contents are corrupted, so
+ =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0* there is n=
o reason to read the other copies, they won't be
+ =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0* any less w=
rong.
+ =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0*/
This sounds like an overstatement to me. You may be dealing with an
error pattern CRC faled to catch, so giving up reading a mirror at
this point seems premature.

Regards,
Andrey
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