On Tue, 6 Jan 2009, Matthew Wilcox wrote:

quoted

This looks ugly. Why doesn't __mutex_lock_common() just set the lock 
owner? Hate seeing it done in the caller that has to re-compute common 
(yeah, yeah, it's cheap) and just looks ugly.

Because __mutex_lock_common() is the slow path.  The fast path is a
couple of assembly instructions in asm/mutex.h.  If the lock isn't
contended, it will never call __mutex_lock_common().

No, that's not it.

Look at the callers. They are _all_ the slow path. They looked like this:

	might_sleep();
	return __mutex_lock_common(lock, TASK_KILLABLE, subclass, _RET_IP_);

Yes, you _also_ need to set the owner in the fast-path, but that's all 
entirely different. This is the debug case, which _always_ calls the 
slow-path.

So what I'm saying is that the slow-path should just set it. And then yes, 
we _also_ need to set it in the fast-path, but at least we don't need to 
set it in all the debug versions that just call the slow path!

			Linus