Thread (10 messages) 10 messages, 4 authors, 2021-09-10

Re: [PATCH v3 1/3] xen/blkfront: read response from backend only once

From: Oleksandr Andrushchenko <Oleksandr_Andrushchenko@epam.com>
Date: 2021-08-03 07:07:52
Also in: lkml, xen-devel

On 02.08.21 22:26, Julien Grall wrote:
Hi,

On 02/08/2021 15:06, Oleksandr Andrushchenko wrote:
quoted
On 30.07.21 13:38, Juergen Gross wrote:
quoted
In order to avoid problems in case the backend is modifying a response
on the ring page while the frontend has already seen it, just read the
response into a local buffer in one go and then operate on that buffer
only.

Signed-off-by: Juergen Gross <jgross@suse.com>
Reviewed-by: Jan Beulich <redacted>
Acked-by: Roger Pau Monné <roger.pau@citrix.com>
---
   drivers/block/xen-blkfront.c | 35 ++++++++++++++++++-----------------
   1 file changed, 18 insertions(+), 17 deletions(-)
diff --git a/drivers/block/xen-blkfront.c b/drivers/block/xen-blkfront.c
index d83fee21f6c5..15e840287734 100644
--- a/drivers/block/xen-blkfront.c
+++ b/drivers/block/xen-blkfront.c
@@ -1496,7 +1496,7 @@ static bool blkif_completion(unsigned long *id,
   static irqreturn_t blkif_interrupt(int irq, void *dev_id)
   {
       struct request *req;
-    struct blkif_response *bret;
+    struct blkif_response bret;
       RING_IDX i, rp;
       unsigned long flags;
       struct blkfront_ring_info *rinfo = (struct blkfront_ring_info *)dev_id;
@@ -1513,8 +1513,9 @@ static irqreturn_t blkif_interrupt(int irq, void *dev_id)
       for (i = rinfo->ring.rsp_cons; i != rp; i++) {
           unsigned long id;
   -        bret = RING_GET_RESPONSE(&rinfo->ring, i);
-        id   = bret->id;
+        RING_COPY_RESPONSE(&rinfo->ring, i, &bret);
As per my understanding copying is still not an atomic operation as the request/response

are multi-byte structures in general. IOW, what prevents the backend from modifying the ring while

we are copying?
Nothing and, I believe, you are never going to be able to ensure atomicity with large structure (at least between entity that doesn't trust each other).

However, what you can do is copying the response once, check that it is consistent and then use it. If it is not consistent, then you can report an error.

This is better than what's currently in tree. IOW we may have multiple read so the code is prone to TOCTOU.
Agree,

Thanks
Cheers,
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