Re: [PATCH v2 14/15] KVM: Terminate memslot walks via used_slots
From: Sean Christopherson <hidden>
Date: 2019-10-24 20:48:30
Also in:
kvm, kvmarm, linux-mips, lkml
On Thu, Oct 24, 2019 at 10:24:09PM +0200, Paolo Bonzini wrote:
On 24/10/19 21:38, Sean Christopherson wrote:quoted
only * its new index into the array is update.s/update/tracked/?
Ya, tracked is better. Waffled between updated and tracked, chose poorly :-)
Returns the changed memslot'squoted
* current index into the memslots array. */ static inline int kvm_memslot_move_backward(struct kvm_memslots *slots, struct kvm_memory_slot *memslot) { struct kvm_memory_slot *mslots = slots->memslots; int i; if (WARN_ON_ONCE(slots->id_to_index[memslot->id] == -1) || WARN_ON_ONCE(!slots->used_slots)) return -1; for (i = slots->id_to_index[memslot->id]; i < slots->used_slots - 1; i++) { if (memslot->base_gfn > mslots[i + 1].base_gfn) break; WARN_ON_ONCE(memslot->base_gfn == mslots[i + 1].base_gfn); /* Shift the next memslot forward one and update its index. */ mslots[i] = mslots[i + 1]; slots->id_to_index[mslots[i].id] = i; } return i; } /* * Move a changed memslot forwards in the array by shifting existing slots with * a lower GFN toward the back of the array. Note, the changed memslot itself * is not preserved in the array, i.e. not swapped at this time, only its new * index into the array is updatedSame here?quoted
* Note, slots are sorted from highest->lowest instead of lowest->highest for * historical reasons.Not just that, the largest slot (with all RAM above 4GB) is also often at the highest address at least on x86.
Ah, increasing the odds of a quick hit on lookup...but only when using a linear search. The binary search starts in the middle, so that optimization is also historical :-)
But we could sort them by size now, so I agree to call these historical reasons.
That wouldn't work with the binary search though.
The code itself is fine, thanks for the work on documenting it. Paolo
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