Each iteration of for_each_child_of_node puts the previous node, but in
the case of a return from the middle of the loop, there is no put, thus
causing a memory leak. Hence add an of_node_put before the return.
Issue found with Coccinelle.
Signed-off-by: Nishka Dasgupta <redacted>
---
drivers/pinctrl/meson/pinctrl-meson.c | 1 +
1 file changed, 1 insertion(+)
diff --git a/drivers/pinctrl/meson/pinctrl-meson.c b/drivers/pinctrl/meson/pinctrl-meson.c
index 596786926209..8bba9d053d9f 100644
--- a/drivers/pinctrl/meson/pinctrl-meson.c
+++ b/drivers/pinctrl/meson/pinctrl-meson.c
@@ -651,6 +651,7 @@ static int meson_pinctrl_parse_dt(struct meson_pinctrl *pc,
continue;
if (gpio_np) {
dev_err(pc->dev, "multiple gpio nodes\n");
+ of_node_put(np);
return -EINVAL;
}
gpio_np = np;--
2.19.1
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