On Fri, Mar 30, 2018 at 10:29:58AM -0400, Sinan Kaya wrote:

The default implementation of mapping writeX() to __raw_writeX() is wrong.
writeX() has stronger ordering semantics. Compiler is allowed to reorder
__raw_writeX().

In the abscence of a write barrier or when using a strongly ordered
architecture, writeX() should at least have a compiler barrier in
it to prevent commpiler from clobbering the execution order.

You want the barrier _before_ the call to __raw_writel() - you need to
ensure that writes to memory are emitted by the compiler _before_ the
write to the hardware - the write to the hardware may start DMA, and it
may be reading data that the program thinks it previously wrote.

Similarly, for readl(), you need the barrier after __raw_readl() to
ensure that other reads in the program aren't scheduled before a
potential DMA status register read.

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