Thread (16 messages) 16 messages, 5 authors, 2018-03-16

[PATCH 1/2] of_pci_irq: add a check to fallback to standard device tree parsing

From: benh@kernel.crashing.org (Benjamin Herrenschmidt)
Date: 2018-02-06 04:06:10
Also in: linux-devicetree, linux-mediatek, linux-pci, lkml

On Tue, 2018-02-06 at 10:38 +0800, Ryder Lee wrote:
I think the code should look at the bridge address <0x0800 ...> we list
in bindings for resolving interrupts in this case, but it seems like it
use the 'pdev->defvn << 8' which is not really we want and will lead to
mismatch.

		interrupt-map-mask = <0xf800 0 0 7>;
		interrupt-map = <0x0000 0 0 1 ...>,
				<0x0000 0 0 2 ...>,
				<0x0000 0 0 3 ...>,
				<0x0000 0 0 4 ...>,

				 0x0800 0 0 1 ...>,
				 0x0800 0 0 2 ...>,
				 0x0800 0 0 3 ...>,
				 0x0800 0 0 4 ...>;
		...
		pcie at 1,0 {
			reg = <0x0800 0 0 0 0>;
			...
		};


Or, alternatively, we could add a interrupt-map property in both child
and root node to solve this. The below example is my original version as
I don't want to change that function either.
The code looks at devfn because it's meant to work for PCI including
when the devices dont have a device node in the DT.

What I'm trying to figure out is what is it that your parent and
children are representing here. Which is/are the root complex ?

What is the actual topology as visible on the PCIe bus (is lspci output
basically) and how does that map to your representation ?
		interrupt-map-mask = <0xf800 0 0 0>;
		interrupt-map = <0x0000 0 0 0 ...>,
				 0x0800 0 0 0 ...>;
		...
		pcie at 1,0 {
			reg = <0x0800 0 0 0 0>;
			#interrupt-cells = <1>;
			interrupt-map-mask = <0 0 0 0>;
			interrupt-map = <0 0 0 0 ...>;
			...
		};

However, I can't find any other similar case in documentation.

Thanks.
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