Thread (21 messages) flat view 21 messages, 3 authors, 2017-08-18
STALE3304d

[PATCH 3/6] kvm: arm64: Convert kvm_set_s2pte_readonly() from inline asm to cmpxchg()

From: Christoffer Dall <hidden>
Date: 2017-08-02 12:48:04

On Wed, Aug 02, 2017 at 10:15:36AM +0100, Catalin Marinas wrote:
Hi Christoffer,

On Tue, Aug 01, 2017 at 01:16:18PM +0200, Christoffer Dall wrote:
quoted
On Tue, Jul 25, 2017 at 02:53:05PM +0100, Catalin Marinas wrote:
quoted
+	pteval_t old_pteval, pteval;
+
+	do {
+		pteval = old_pteval = READ_ONCE(pte_val(*pte));
+		pteval &= ~PTE_S2_RDWR;
+		pteval |= PTE_S2_RDONLY;
+	} while (cmpxchg_relaxed(&pte_val(*pte), old_pteval, pteval) !=
+		 old_pteval);
I'm wondering if the READ_ONCE for old_pteval is strictly necessary, or
if that's really for the pteval.  Actually, I'm a little unsure whether
this is equivalent to

	old_pteval = READ_ONCE(pte_val(*pte));
	pteval = old_pteval;

or

	old_pteval = READ_ONCE(pte_val(*pte));
	pteval = READ_ONCE(pte_val(*pte));

I think it's the former, which I also think is correct,
I think so too.
quoted
but the reason
I'm going down this road is that we have a use of cmpxchg() in the VGIC
code, which doesn't use READ_ONCE for the old value (~
vgic-mmio-v3.c:404), and I also found other occurences of this in the
kernel, so I'm wondering if the VGIC code is broken or we're being
overly careful here, or if this is necessary because hardware can update
the value behind our backs in this case?
We use it because the compiler may decide it's short on registers and
instead of saving old_pteval on the stack it reads it again from memory
just before cmpxchg, so we would miss any update to *pte done by the
hardware. In practice, I've never seen (on arm64) gcc generating two
loads to *pte without READ_ONCE but maybe I haven't tried hard enough.

We should probably fix the VGIC code as well as a precaution, just in
case the compiler tries to get smarter in the future.
Sounds like a plan, I'll cook up a patch.

Thanks,
-Christoffer
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