Thread (39 messages) 39 messages, 5 authors, 2016-11-24

[PATCH v16 14/15] clocksource/drivers/arm_arch_timer: Add GTDT support for memory-mapped timer

From: mark.rutland@arm.com (Mark Rutland)
Date: 2016-11-18 20:20:46
Also in: linux-acpi, linux-watchdog, lkml

On Wed, Nov 16, 2016 at 09:49:07PM +0800, fu.wei at linaro.org wrote:
quoted hunk ↗ jump to hunk
From: Fu Wei <redacted>

The patch add memory-mapped timer register support by using the
information provided by the new GTDT driver of ACPI.

Signed-off-by: Fu Wei <redacted>
---
 drivers/clocksource/arm_arch_timer.c | 26 +++++++++++++++++++++++++-
 1 file changed, 25 insertions(+), 1 deletion(-)
diff --git a/drivers/clocksource/arm_arch_timer.c b/drivers/clocksource/arm_arch_timer.c
index c494ca8..0aad60a 100644
--- a/drivers/clocksource/arm_arch_timer.c
+++ b/drivers/clocksource/arm_arch_timer.c
@@ -1067,7 +1067,28 @@ CLOCKSOURCE_OF_DECLARE(armv7_arch_timer_mem, "arm,armv7-timer-mem",
 		       arch_timer_mem_of_init);
 
 #ifdef CONFIG_ACPI_GTDT
-/* Initialize per-processor generic timer */
+static int __init arch_timer_mem_acpi_init(void)
+{
+	struct arch_timer_mem *timer_mem;
+	int ret = 0;
+	int i = 0;
+
+	timer_mem = kzalloc(sizeof(*timer_mem), GFP_KERNEL);
Why do you need it zeroed? You don't clear it between iterations, so
either you don't need this, or you have a bug in the loop.
+	if (!timer_mem)
+		return -ENOMEM;
+
+	while (!gtdt_arch_timer_mem_init(timer_mem, i)) {
Huh?

Why doesn't GTDT expose a function to fill in the entire arch_timer_mem
in one go?

There shouldn't be multiple instances, as far as I am aware. Am I
mistaken?
+		ret = arch_timer_mem_init(timer_mem);
+		if (ret)
+			break;
+		i++;
+	}
+
+	kfree(timer_mem);
+	return ret;
+}

Regardless, arch_timer_mem is small enough that you don't need dynamic
allocaiton. Just put it on the stack, e.g.

static int __init arch_timer_mem_acpi_init(void)
{
	int i = 0;
	struct arch_timer_mem timer_mem;

	while (!gtdt_arch_timer_mem_init(timer_mem, i)) {
		int ret = arch_timer_mem_init();
		if (ret)
			return ret;
		i++
	}

	return 0;
}

Thanks,
Mark.
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