Thread (12 messages) 12 messages, 5 authors, 2014-12-05

[RFC v2] arm:extend the reserved mrmory for initrd to be page aligned

From: Russell King - ARM Linux <hidden>
Date: 2014-09-15 11:33:35
Also in: linux-arm-msm, linux-mm, lkml

On Mon, Sep 15, 2014 at 07:07:20PM +0800, Wang, Yalin wrote:
this patch extend the start and end address of initrd to be page aligned,
so that we can free all memory including the un-page aligned head or tail
page of initrd, if the start or end address of initrd are not page
aligned, the page can't be freed by free_initrd_mem() function.
Better, but I think it's more complicated than it needs to be:
quoted hunk ↗ jump to hunk
Signed-off-by: Yalin Wang <redacted>
---
 arch/arm/mm/init.c   | 19 +++++++++++++++++--
 arch/arm64/mm/init.c | 37 +++++++++++++++++++++++++++++++++----
 2 files changed, 50 insertions(+), 6 deletions(-)
diff --git a/arch/arm/mm/init.c b/arch/arm/mm/init.c
index 659c75d..8490b70 100644
--- a/arch/arm/mm/init.c
+++ b/arch/arm/mm/init.c
@@ -277,6 +277,8 @@ phys_addr_t __init arm_memblock_steal(phys_addr_t size, phys_addr_t align)
 void __init arm_memblock_init(const struct machine_desc *mdesc)
 {
 	/* Register the kernel text, kernel data and initrd with memblock. */
+	phys_addr_t phys_initrd_start_orig __maybe_unused;
+	phys_addr_t phys_initrd_size_orig __maybe_unused;
 #ifdef CONFIG_XIP_KERNEL
 	memblock_reserve(__pa(_sdata), _end - _sdata);
 #else
@@ -289,6 +291,13 @@ void __init arm_memblock_init(const struct machine_desc *mdesc)
 		phys_initrd_size = initrd_end - initrd_start;
 	}
 	initrd_start = initrd_end = 0;
+	phys_initrd_start_orig = phys_initrd_start;
+	phys_initrd_size_orig = phys_initrd_size;
+	/* make sure the start and end address are page aligned */
+	phys_initrd_size = round_up(phys_initrd_start + phys_initrd_size, PAGE_SIZE);
+	phys_initrd_start = round_down(phys_initrd_start, PAGE_SIZE);
+	phys_initrd_size -= phys_initrd_start;
+
 	if (phys_initrd_size &&
 	    !memblock_is_region_memory(phys_initrd_start, phys_initrd_size)) {
 		pr_err("INITRD: 0x%08llx+0x%08lx is not a memory region - disabling initrd\n",
@@ -305,9 +314,10 @@ void __init arm_memblock_init(const struct machine_desc *mdesc)
 		memblock_reserve(phys_initrd_start, phys_initrd_size);
 
 		/* Now convert initrd to virtual addresses */
-		initrd_start = __phys_to_virt(phys_initrd_start);
-		initrd_end = initrd_start + phys_initrd_size;
+		initrd_start = __phys_to_virt(phys_initrd_start_orig);
+		initrd_end = initrd_start + phys_initrd_size_orig;
 	}
+
I think all the above is entirely unnecessary.  The memblock APIs
(especially memblock_reserve()) will mark the overlapped pages as reserved
- they round down the starting address, and round up the end address
(calculated from start + size).

Hence, this:
quoted hunk ↗ jump to hunk
@@ -636,6 +646,11 @@ static int keep_initrd;
 void free_initrd_mem(unsigned long start, unsigned long end)
 {
 	if (!keep_initrd) {
+		if (start == initrd_start)
+			start = round_down(start, PAGE_SIZE);
+		if (end == initrd_end)
+			end = round_up(end, PAGE_SIZE);
+
 		poison_init_mem((void *)start, PAGE_ALIGN(end) - start);
 		free_reserved_area((void *)start, (void *)end, -1, "initrd");
 	}
is the only bit of code you likely need to achieve your goal.

Thinking about this, I think that you are quite right to align these.
The memory around the initrd is defined to be system memory, and we
already free the pages around it, so it *is* wrong not to free the
partial initrd pages.

Good catch.

-- 
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