pci-mvebu driver on km_kirkwood
From: Thomas Petazzoni <hidden>
Date: 2014-02-21 17:05:08
Also in:
linux-pci
Dear Jason Gunthorpe, On Fri, 21 Feb 2014 09:39:02 -0700, Jason Gunthorpe wrote:
On Fri, Feb 21, 2014 at 02:47:08PM +0100, Thomas Petazzoni wrote:quoted
*) I don't know if the algorithm to split the BAR into multiple windows is going to be trivial.physaddr_t base,size; while (size != 0) { physaddr_t window_size = 1 << log2_round_down(size); create_window(base,window_size); base += window_size; size -= window_size; } At the very worst log2_round_down is approxmiately unsigned int log2_round_down(unsigned int val) { unsigned int res = 0; while ((1<<res) <= val) res++; return res - 1; } Minimum PCI required alignment for windows is 1MB so it will always work out into some number of mbus windows..
Interesting! Thanks! Now I have another question: our mvebu_pcie_align_resource() function makes sure that the base address of the BAR is aligned on its size, because it is a requirement of MBus windows. However, if you later split the BAR into multiple windows, will this continue to work out? Let's take an example: a 96 MB BAR. If it gets put at 0xe0000000, then no problem: we create one 64 MB window at 0xe0000000 and a 32 MB window at 0xe4000000. Both base addresses are aligned on the size of the window. However, if the 96 MB BAR gets put at 0xea000000 (which is aligned on a 96 MB boundary, as required by our mvebu_pcie_align_resource). We create one 64 MB window at 0xea000000, and one 32 MB window at 0xee000000. Unfortunately, while 0xea000000 is aligned on a 96 MB boundary, it is not aligned on a 64 MB boundary, so the 64 MB window we have created is wrong. Which also makes me think that our mvebu_pcie_align_resource() function uses round_up(start, size), which most likely doesn't work with non power-of-two sizes. Thomas -- Thomas Petazzoni, CTO, Free Electrons Embedded Linux, Kernel and Android engineering http://free-electrons.com