[RFC/RFT 1/3] iop: clocksource support

2009/9/1 Mikael Pettersson [off-list ref]:

?> Calculate this using the algorithm in arch/mips/kernel/time.c
?> they have a dynamically changing clocksource...

The algorithm always computes the largest shift/mult pair that
solves the equation:

? ? ? ?// 0 <= shift && shift <= 32
? ? ? ?u64 mult = ((u64)1E9 << shift) / hz;
? ? ? ?(mult >> 32) == 0

Can I assume that this is to minimize precision loss?

So I think, I asked the question of how to calculate div but noone
answered IIRC, then I found the MIPS code and it contained this
clue. Ralf Baechle from the MIPS camp wrote this code so lets
ask him.

Linus Walleij