Thread (63 messages) 63 messages, 6 authors, 2014-07-15

Re: [PATCH 01/11] qspinlock: A simple generic 4-byte queue spinlock

From: Konrad Rzeszutek Wilk <hidden>
Date: 2014-06-27 14:23:55
Also in: kvm, lkml, virtualization

On Mon, Jun 23, 2014 at 05:56:50PM +0200, Peter Zijlstra wrote:
On Mon, Jun 16, 2014 at 04:49:18PM -0400, Konrad Rzeszutek Wilk wrote:
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quoted
Index: linux-2.6/kernel/locking/mcs_spinlock.h
===================================================================
--- linux-2.6.orig/kernel/locking/mcs_spinlock.h
+++ linux-2.6/kernel/locking/mcs_spinlock.h
@@ -17,6 +17,7 @@
 struct mcs_spinlock {
 	struct mcs_spinlock *next;
 	int locked; /* 1 if lock acquired */
+	int count;
This could use a comment.
like so?

	int count; /* nesting count, see qspinlock.c */
/* nested level -  in user, softirq, hard irq or nmi context. */ ?
quoted
quoted
+static inline u32 encode_tail(int cpu, int idx)
+{
+	u32 tail;
+
+	tail  = (cpu + 1) << _Q_TAIL_CPU_OFFSET;
+	tail |= idx << _Q_TAIL_IDX_OFFSET; /* assume < 4 */
Should there an

ASSSERT (idx < 4)

just in case we screw up somehow (I can't figure out how, but
that is partially why ASSERTS are added).
#ifdef CONFIG_DEBUG_SPINLOCK
	BUG_ON(idx > 3);
#endif

might do, I suppose.
<nods>
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quoted
+/**
+ * queue_spin_lock_slowpath - acquire the queue spinlock
+ * @lock: Pointer to queue spinlock structure
+ * @val: Current value of the queue spinlock 32-bit word
+ *
+ * (queue tail, lock bit)
Except it is not a lock bit. It is a lock uint8_t.
It is indeed, although that's an accident of implementation. I could do
s/bit// and not mention the entire storage angle at all?
I think giving as much details as possible is good.

What you said 'accident of implementation' is a could be woven
in there?
quoted
Is the queue tail at this point the composite of 'cpu|idx'?
Yes, as per {en,de}code_tail() above.
quoted
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+ *
+ *              fast      :    slow                                  :    unlock
+ *                        :                                          :
+ * uncontended  (0,0)   --:--> (0,1) --------------------------------:--> (*,0)
+ *                        :       | ^--------.                    /  :
+ *                        :       v           \                   |  :
+ * uncontended            :    (n,x) --+--> (n,0)                 |  :
So many CPUn come in right? Is 'n' for the number of CPUs?
Nope, 'n' for any one specific tail, in particular the first one to
arrive. This is the 'uncontended queue' case as per the label, so we
need a named value for the first, in order to distinguish between the
state to the right (same tail, but unlocked) and the state below
(different tail).
quoted
quoted
+ *   queue                :       | ^--'                          |  :
+ *                        :       v                               |  :
+ * contended              :    (*,x) --+--> (*,0) -----> (*,1) ---'  :
+ *   queue                :         ^--'                             :
And here um, what are the '*' for? Are they the four different
types of handlers that can be nested? So task, sofitrq, hardisk, and
nmi?
'*' as in wildcard, any tail, specifically not 'n'.
Ah, thank you for the explanation! Would it be possible to include
that in the comment please?
quoted
quoted
+void queue_spin_lock_slowpath(struct qspinlock *lock, u32 val)
+{
+	struct mcs_spinlock *prev, *next, *node;
+	u32 new, old, tail;
+	int idx;
+
+	BUILD_BUG_ON(CONFIG_NR_CPUS >= (1U << _Q_TAIL_CPU_BITS));
+
+	node = this_cpu_ptr(&mcs_nodes[0]);
+	idx = node->count++;
If this is the first time we enter this, wouldn't idx end up
being 1?
Nope, postfix ++ returns first and increments later.
<blushes> Yes it does.
quoted
quoted
+	tail = encode_tail(smp_processor_id(), idx);
+
+	node += idx;
Meaning we end up skipping the 'mcs_nodes[0]' one altogether - even
on the first 'level' (task, softirq, hardirq, nmi)? Won't that
cause us to blow past the array when we are nested at the nmi
handler?
Seeing how its all static storage, which is automagically initialized to
0, combined with the postfix ++ (as opposed to the prefix ++) we should
be getting 0 here.
I've no idea what I was thinking, but thank you for setting me straight.
quoted
quoted
+	node->locked = 0;
+	node->next = NULL;
+
+	/*
+	 * trylock || xchg(lock, node)
+	 *
+	 * 0,0 -> 0,1 ; trylock
+	 * p,x -> n,x ; prev = xchg(lock, node)
I looked at that for 10 seconds and I was not sure what you meant.
Is this related to the MCS document you had pointed to? It would help
if you mention that the comments follow the document. (But they
don't seem to)

I presume what you mean is that if we are the next after the
lock-holder we need only to update the 'next' (or the
composite value of smp_processor_idx | idx) to point to us.

As in, swap the 'L' with 'I' (looking at the doc)
They are the 'tail','lock' tuples, so this composite atomic operation
completes either:

  0,0 -> 0,1  -- we had no tail, not locked; into: no tail, locked.

OR

  p,x -> n,x  -- tail was p; into: tail is n; preserving locked.
Oh this is good!
quoted
quoted
+	 */
+	for (;;) {
+		new = _Q_LOCKED_VAL;
+		if (val)
Could you add a comment here, like this:

/*
 * N.B. Initially 'val' will have some value (as we are called
 * after the _Q_LOCKED_VAL could not be set by queue_spin_lock).
 * But on subsequent iterations, either the lock holder will
 * decrement the val (queue_spin_unlock - to zero) and we
 * needn't to record our status in the queue as we have set the
 * Q_LOCKED_VAL (new) and are the lock holder. Or we are next
 * in line and need to record our 'next' (aka, smp_processor_id() | idx)
 * position. */
 */
The idea was that:

  0,0 -> 0,1
  p,x -> n,x

Completely covers what this composite atomic does.
quoted
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+			new = tail | (val & _Q_LOCKED_MASK);
+
+		old = atomic_cmpxchg(&lock->val, val, new);
+		if (old == val)
+			break;
+
+		val = old;
+	}
+
+	/*
+	 * we won the trylock; forget about queueing.
+	 */
+	if (new == _Q_LOCKED_VAL)
+		goto release;
+
+	/*
+	 * if there was a previous node; link it and wait.
+	 */
+	if (old & ~_Q_LOCKED_MASK) {
+		prev = decode_tail(old);
+		ACCESS_ONCE(prev->next) = node;
+
+		arch_mcs_spin_lock_contended(&node->locked);
+	}
+
+	/*
+	 * we're at the head of the waitqueue, wait for the owner to go away.
+	 *
+	 * *,x -> *,0
+	 */
+	while ((val = atomic_read(&lock->val)) & _Q_LOCKED_MASK)
+		cpu_relax();
+
+	/*
+	 * claim the lock:
+	 *
+	 * n,0 -> 0,1 : lock, uncontended
+	 * *,0 -> *,1 : lock, contended
+	 */
+	for (;;) {
+		new = _Q_LOCKED_VAL;
+		if (val != tail)
+			new |= val;
You lost me here. If we are at the head of the queue, and the owner
has called queue_spin_unlock (hence made us get out of the 'val = atomic_read'
loop, how can val != tail?
Remember:
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+	tail = encode_tail(smp_processor_id(), idx);
So if value != tail, that means the tail pointer doesn't point to us
anymore, another cpu/idx queued itself and is now last.
quoted
I suspect it has something to do with the comment, but I am still unsure
what it means.

Could you help a bit in explaining it in English please?
(refer to the state diagram, if we count states left->right,
top->bottom, then this is: 5->2 or 7->8

 n,0 -> 0,1:

   the lock is free and the tail points to the first queued; this means
   that unqueueing implies wiping the tail, at the same time, acquire
   the lock.

 *,0 -> *,1:

   the lock is free and the tail doesn't point to the first queued; this
   means that unqueueing doesn't touch the tail pointer but only sets
   the lock.
quoted
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+
+		old = atomic_cmpxchg(&lock->val, val, new);
+		if (old == val)
+			break;
+
+		val = old;
+	}
+
+	/*
+	 * contended path; wait for next, release.
+	 */
+	if (new != _Q_LOCKED_VAL) {
Hm, wouldn't it be just easier to do a 'goto restart' where
restart label points at the first loop statement? Ah never
mind - we have already inserted ourselves in the previous's
node.

But that is confusing - we have done: "prev->next = node;"

And then exited out of 'val = atomic_read(&lock->val))' which
suggests that queue_spin_unlock has called us. How can we be
contended again?
We're not contended again; we're in the 'contended queued' case, which
means that 'tail' didn't point to us anymore, in that case, we must kick
our next node such that it will now drop out of
arch_mcs_spin_lock_contended() and goes wait on the 'locked' state.
<nods>
So what we do here is wait for 'node->next' to be set; it might still be
NULL if the other cpu is between:

  prev = xchg(lock->tail, node);

and:

  prev->next = node;

Once we observe the next node, we call arch_mcs_spin_unlock_contended()
on it, which sets its mcs_spinlock::locked and makes the new 'top of
queue' drop out of arch_mcs_spin_lock_contended and spin on the 'locked'
state as said above.
Thank you for your detailed explanation!
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