Thread (44 messages) flat view 44 messages, 5 authors, 2022-01-20

Re: [PATCH v0.9.1 3/6] sched/umcg: implement UMCG syscalls

From: Peter Zijlstra <peterz@infradead.org>
Date: 2021-11-29 23:06:44
Also in: linux-mm, lkml

On Mon, Nov 29, 2021 at 09:34:49AM -0800, Peter Oskolkov wrote:
On Mon, Nov 29, 2021 at 8:41 AM Peter Zijlstra [off-list ref] wrote:
quoted
However, do note this whole scheme fundamentally has some of that, the
moment the syscall unblocks until sys_exit is 'unmanaged' runtime for
all tasks, they can consume however much time the syscall needs there.

Also, timeout on sys_umcg_wait() gets you the exact same situation (or
worse, multiple running workers).
It should not. Timed out workers should be added to the runnable list
and not become running unless a server chooses so. So sys_umcg_wait()
with a timeout should behave similarly to a normal sleep, in that the
server is woken upon the worker blocking, and upon the worker wakeup
the worker is added to the woken workers list and waits for a server
to run it. The only difference is that in a sleep the worker becomes
BLOCKED, while in sys_umcg_wait() the worker is RUNNABLE the whole
time.
OK, that's somewhat subtle and I hadn't gotten that either.

Currently it return -ETIMEDOUT in RUNNING state for both server and
worker callers.

Let me go fix that then.
quoted
quoted
Another big concern I have is that you removed UMCG_TF_LOCKED. I
OOh yes, I forgot to mention that. I couldn't figure out what it was
supposed to do.
quoted
definitely needed it to guard workers during "sched work" in the
userspace in my approach. I'm not sure if the flag is absolutely
needed with your approach, but most likely it is - the kernel-side
scheduler does lock tasks and runqueues and disables interrupts and
migrations and other things so that the scheduling logic is not
hijacked by concurrent stuff. Why do you assume that the userspace
scheduling code does not need similar protections?
I've not yet come across a case where this is needed. Migration for
instance is possible when RUNNABLE, simply write ::server_tid before
::state. Userspace just needs to make sure who actually owns the task,
but it can do that outside of this state.

But like I said; I've not yet done the userspace part (and I lost most
of today trying to install a new machine), so perhaps I'll run into it
soon enough.
The most obvious scenario where I needed locking is when worker A
wants to context switch into worker B, while another worker C wants to
context switch into worker A, and worker A pagefaults. This involves:

worker A context: worker A context switches into worker B:

- worker B::server_tid = worker A::server_tid
- worker A::server_tid = none
- worker A::state = runnable
- worker B::state = running
- worker A::next_tid = worker B
- worker A calls sys_umcg_wait()

worker B context: before the above completes, worker C wants to
context switch into worker A, with similar steps.

"interrupt context": in the middle of the mess above, worker A pagefaults

Too many moving parts. UMCG_TF_LOCKED helped me make this mess
manageable. Maybe without pagefaults clever ordering of the operations
listed above could make things work, but pagefaults mess things badly,
so some kind of "preempt_disable()" for the userspace scheduling code
was needed, and UMCG_TF_LOCKED was the solution I had.
I'm not sure I'm following. For this to be true A and C must be running
on a different server right?

So we have something like:

	S0 running A			S1 running B

Therefore:

	S0::state == RUNNABLE		S1::state == RUNNABLE
	A::server_tid == S0.tid		B::server_tid == S1.tid
	A::state == RUNNING		B::state == RUNNING

Now, you want A to switch to C, therefore C had better be with S0, eg we
have:

	C::server_tid == S0.tid
	C::state == RUNNABLE

So then A does:

	A::next_tid = C.tid;
	sys_umcg_wait();

Which will:

	pin(A);
	pin(S0);

	cmpxchg(A::state, RUNNING, RUNNABLE);

	next_tid = A::next_tid; // C

	enqueue(S0::runnable, A);

At which point B steals S0's runnable queue, and tries to make A go.

					runnable = xchg(S0::runnable_list_ptr, NULL); // == A
					A::server_tid = S1.tid;
					B::next_tid = A.tid;
					sys_umcg_wait();

	wake(C)
	  cmpxchg(C::state, RUNNABLE, RUNNING); <-- *fault*


Something like that, right?

What currently happens is that S0 goes back to S0 and S1 ends up in A.
That is, if, for any reason we fail to wake next_tid, we'll wake
server_tid.

So then S0 wakes up and gets to re-evaluate life. If it has another
worker it can go run that, otherwise it can try and steal a worker
somewhere or just idle out.

Now arguably, the only reason A->C can fault is because C is garbage, at
which point your program is malformed and it doesn't matter what
happens one way or the other.
Keyboard shortcuts
hback out one level
jnext message in thread
kprevious message in thread
ldrill in
Escclose help / fold thread tree
?toggle this help