Re: strace of io_uring events?
From: Jens Axboe <axboe@kernel.dk>
Date: 2020-07-21 18:39:29
Also in:
io-uring, linux-fsdevel, lkml
On 7/21/20 11:44 AM, Andy Lutomirski wrote:
On Tue, Jul 21, 2020 at 10:30 AM Jens Axboe [off-list ref] wrote:quoted
On 7/21/20 11:23 AM, Andy Lutomirski wrote:quoted
On Tue, Jul 21, 2020 at 8:31 AM Jens Axboe [off-list ref] wrote:quoted
On 7/21/20 9:27 AM, Andy Lutomirski wrote:quoted
On Fri, Jul 17, 2020 at 1:02 AM Stefano Garzarella [off-list ref] wrote:quoted
On Thu, Jul 16, 2020 at 08:12:35AM -0700, Kees Cook wrote:quoted
On Thu, Jul 16, 2020 at 03:14:04PM +0200, Stefano Garzarella wrote:quoted
quoted
access (IIUC) is possible without actually calling any of the io_uring syscalls. Is that correct? A process would receive an fd (via SCM_RIGHTS, pidfd_getfd, or soon seccomp addfd), and then call mmap() on it to gain access to the SQ and CQ, and off it goes? (The only glitch I see is waking up the worker thread?)It is true only if the io_uring istance is created with SQPOLL flag (not the default behaviour and it requires CAP_SYS_ADMIN). In this case the kthread is created and you can also set an higher idle time for it, so also the waking up syscall can be avoided.I stared at the io_uring code for a while, and I'm wondering if we're approaching this the wrong way. It seems to me that most of the complications here come from the fact that io_uring SQEs don't clearly belong to any particular security principle. (We have struct creds, but we don't really have a task or mm.) But I'm also not convinced that io_uring actually supports cross-mm submission except by accident -- as it stands, unless a user is very careful to only submit SQEs that don't use user pointers, the results will be unpredictable.How so?Unless I've missed something, either current->mm or sqo_mm will be used depending on which thread ends up doing the IO. (And there might be similar issues with threads.) Having the user memory references end up somewhere that is an implementation detail seems suboptimal.current->mm is always used from the entering task - obviously if done synchronously, but also if it needs to go async. The only exception is a setup with SQPOLL, in which case ctx->sqo_mm is the task that set up the ring. SQPOLL requires root privileges to setup, and there's no task entering the io_uring at all necessarily. It'll just submit sqes with the credentials that are registered with the ring.Really? I admit I haven't fully followed how the code works, but it looks like anything that goes through the io_queue_async_work() path will use sqo_mm, and can't most requests that end up blocking end up there? It looks like, even if SQPOLL is not set, the mm used will depend on whether the request ends up blocking and thus getting queued for later completion. Or does some magic I missed make this a nonissue.
No, you are wrong. The logic works as I described it.
quoted
This is just one known use case, there may very well be others. Outside of SQPOLL, which is special, I don't see a reason to restrict this. Given that you may have a fuller understanding of it after the above explanation, please clearly state what problem you're seeing that warrants a change.I see two fundamental issues: 1. The above. This may be less of an issue than it seems to me, but, if you submit io from outside sqo_mm, the mm that ends up being used depends on whether the IO is completed from io_uring_enter() or from the workqueue. For something like Postgres, I guess this is okay because the memory is MAP_ANONYMOUS | MAP_SHARED and the pointers all point the same place regardless.
No that is incorrect. If you disregard SQPOLL, then the 'mm' is always who submitted it.
2. If you create an io_uring and io_uring_enter() it from a different mm, it's unclear what seccomp is supposed to do. (Or audit, for that matter.) Which task did the IO? Which mm did the IO? Whose sandbox is supposed to be applied?
Also doesn't seem like a problem, if you understand the 'mm' logic above. Unless SQPOLL is used, the entering tasks mm will be used. There's no mixing of tasks and mm outside of that. -- Jens Axboe