Re: [PATCH] Fix printing when no interrupt is allocated
From: Daniel J Blueman <hidden>
Date: 2012-10-31 09:03:09
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Hi Len, On 19/10/2012 09:21, Joe Perches wrote:
quoted hunk ↗ jump to hunk
On Fri, 2012-10-19 at 08:33 +0800, Daniel J Blueman wrote:quoted
Previously a new line is implicitly added in the no GSI case: [ 7.185182] pci 0001:00:12.0: can't derive routing for PCI INT A [ 7.191352] pci 0001:00:12.0: PCI INT A: no GSI [ 7.195956] - using ISA IRQ 10 The code thus prints a blank line where no legacy IRQ is available: [ 1.650124] pci 0000:00:14.0: can't derive routing for PCI INT A [ 1.650126] pci 0000:00:14.0: PCI INT A: no GSI [ 1.650126] [ 1.650180] pci 0000:00:14.0: can't derive routing for PCI INT A Fix this by making the newline explicit and removing the superfluous one.I think this is a better fix: drivers/acpi/pci_irq.c | 11 ++++++----- 1 file changed, 6 insertions(+), 5 deletions(-)diff --git a/drivers/acpi/pci_irq.c b/drivers/acpi/pci_irq.c index 0eefa12..9b98f9f 100644 --- a/drivers/acpi/pci_irq.c +++ b/drivers/acpi/pci_irq.c@@ -459,19 +459,20 @@ int acpi_pci_irq_enable(struct pci_dev *dev) */ if (gsi < 0) { u32 dev_gsi; - dev_warn(&dev->dev, "PCI INT %c: no GSI", pin_name(pin)); /* Interrupt Line values above 0xF are forbidden */ if (dev->irq > 0 && (dev->irq <= 0xF) && (acpi_isa_irq_to_gsi(dev->irq, &dev_gsi) == 0)) { - printk(" - using ISA IRQ %d\n", dev->irq); + dev_warn(&dev->dev, + "PCI INT %c: no GSI - using ISA IRQ %d\n", + pin_name(pin), dev->irq); acpi_register_gsi(&dev->dev, dev_gsi, ACPI_LEVEL_SENSITIVE, ACPI_ACTIVE_LOW); - return 0; } else { - printk("\n"); - return 0; + dev_warn(&dev->dev, "PCI INT %c: no GSI\n", + pin_name(pin)); } + return 0; } rc = acpi_register_gsi(&dev->dev, gsi, triggering, polarity);
We're still seeing this in 3.7-rc3. Any preference to the approach here? Thanks, Daniel -- Daniel J Blueman Principal Software Engineer, Numascale Asia