Network Byte order not reached reading from a sock RAW
From: Mandeep Sandhu <hidden>
Date: 2012-10-17 05:18:06
Could you provide the piece(s) of code where kernel does this type of operation ? Of course just suggest me some file where search, I am really curios and I would like understand better this question but at the same time I am unable to find the files where look for.
I had a written a Realtek ethernet card driver long time back (its been almost 6yrs since) for my own curiosity. So my memory right now is sketchy! :) You can start off by gong through the n/w device driver for some card (eg: drivers/net/8139too.c) and work your way up the stack (next you can look at net/ipv4/ip_input.c). The basic idea is that when a packet is rx'ed by the n/w device, it creates a sk_buff (socket buffer) and passes this up the stack where it's processed by the various protocol layers (IP, TCP etc). Though I'm not certain if the n/w device driver populates the various skb fields in the n/w or host byte order. Only inspecting the code will tell. HTH, -mandeep
Many thanks, Pietro. -----Original Message----- From: Mandeep Sandhu [mailto:mandeepsandhu.chd at gmail.com] Sent: luned? 15 ottobre 2012 10:33 To: Pietro Paolini Cc: kernelnewbies at kernelnewbies.org Subject: Re: Network Byte order not reached reading from a sock RAW On Mon, Oct 15, 2012 at 1:16 PM, Pietro Paolini [off-list ref] wrote:quoted
Hello, Thanks for your answer, my question is why when I read from the buffer data is already in host byte order and not in network byte order.The 'raw' payload in your packet might still be in the n/w byte order and you will have to convert it using the ntoh*() functions (I'm not 100% sure about this though). CMIIW, as I haven't touched sockets in a long time! :) HTH, -mandeepquoted
Thanks Pietro Paolini. From: Mandeep Sandhu [mailto:mandeepsandhu.chd at gmail.com] Sent: sabato 13 ottobre 2012 05:30 To: Pietro Paolini Cc: kernelnewbies at kernelnewbies.org Subject: Re: Network Byte order not reached reading from a sock RAW On Oct 12, 2012 9:36 PM, "Pietro Paolini" [off-list ref] wrote:quoted
Hello, I am struggling with the byte order question on a x86_32 arch, I am doing some modifications on a program which actually works fine on a MIPS arch. I do a reading from a RAW socket in this way: /* Configure socket */ if ((fd = socket(AF_INET, SOCK_RAW, IPPROTO_IGMP)) < 0) { perror("Error on socket creation, exit"); exit(1); } .... if (setsockopt(fd, IPPROTO_IP, IP_PKTINFO, (void *)&va, sizeof(va))) { perror("Error on setsockopt, exit"); exit(1); } va = 0; .... .... struct msghdr mhdr; struct __in_pktinfo *pktinfo = NULL; ... ... nrd = recvmsg(env->mrouter_fd, &mhdr, 0); ... ip = (struct iphdr *)iov.iov_base; When I print the saddr (or daddr) of the received ip packet it is printed as host byte order instead of what I am expecting, the network byte order. I can just use the htonl() family functions for solve the problem but I would like understand if it is the normal behavior or if there is an issues on my code, or if the device driver of my NIC can influence the question.I think you should use ntoh*() functions when accessing data rx'ed from the n/w. Network byte order is big endian and your host is little endian, so you'll have convert it to the right order before accessing. You should use hton*() functions when tx'ing data. CMIIW. HTH, -mandeepquoted
Many thanks, Pietro. _______________________________________________ Kernelnewbies mailing list Kernelnewbies at kernelnewbies.org http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies