Hi Enrico,

I am not sure.

No, because 32bit code will tell the datatype size and i think pointer 
variable depends on architecture.
So 64 bit processor needs 64 address line to point the data location. So 
pointer variable needs to be 8 byte.

please correct me if i am worng.

Thanks,
Prabhu


Enrico Granata wrote:

What if one is compiling 32bit code on a 64bit processor? Would 4 be 
an acceptable result to you in that case?

/Enrico Granata/
/Computer Science & Engineering Department (EBU3B) - //Room 3240/
/office phone 858 534 9914/
/University of California, San Diego/

On Jan 26, 2011, at 10:07 PM, prabhu wrote:

quoted

Hi Dear,

I just wanna to know my processor architecture(32bit or 64 bit) through
c programming.

According to me the sizeof of pointer will give the result. Like below
coding.

int main()
{
   int *ptr;
   printf("%d",sizeof(ptr));
}

Please correct me if i am wrong...

Any suggestion or help would be appreciated.

Thanks,
Prabhu

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