Re: [PATCH V4 1/1] Replace SID with domain/username
From: Matthias Aßhauer <hidden>
Date: 2024-01-03 08:21:20
Possibly related (same subject, not in this thread)
- 2024-01-03 · Re: [PATCH V4 1/1] Replace SID with domain/username · Junio C Hamano <hidden>
- 2024-01-02 · [PATCH V4 1/1] Replace SID with domain/username · Sören Krecker <hidden>
On Tue, 2 Jan 2024, Junio C Hamano wrote:
Sören Krecker [off-list ref] writes:quoted
Replace SID with domain/username in error message, if owner of repository and user are not equal on windows systems. Each user should have a unique SID (https://learn.microsoft.com/en-us/windows-server/identity/ad-ds/manage/understand-security-identifiers#what-are-security-identifiers).That paragraph your URL refers to does say that a SID that is used for an account will never be reused to identify a different account. But I am not sure if it means a user will never be assigned more than one SID (in other words, the reverse is not necessarily true).
To my knowledge a user account will never have multiple active SIDs, but the documentation of LookupAccountSidA [1] explicitly mentions that it does look up historic SIDs.
In addition to looking up SIDs for local accounts, local domain accounts, and explicitly trusted domain accounts, LookupAccountSid can look up SIDs for any account in any domain in the forest, including SIDs that appear only in the SIDhistory field of an account in the forest. The SIDhistory field stores former SIDs of an account that has been moved from another domain.
[1] https://learn.microsoft.com/en-us/windows/win32/api/winbase/nf-winbase-lookupaccountsida#remarks
The paragraph also mentions that a SID can identify a non-user entity like a computer account (as opposed to "a user account")---I do not know what its implications are in the context of this patch, though.quoted
This means that domain/username is not a loss of information.This statement does not (grammatically) make sense, but more importantly, loss of information may not be a bad thing in this case. If more than one SIDs are given to a user account and processes working for that account, these different SIDs may be translated, by using LookupAccountSidA(), to the same string for a single user@domain, and it would be an operation that loses information in that sense. But if what we *care* about is user@domain between the current process and the owner of the directory in question being the same (or not), then such a loss of information is a *good* thing.
This patch only changes the output of our error message, though. It does not change what ownership information we actually compare. So if we had a hypothetical user Bob that was part of the domain example.com (SID S-1-5-21-100000001-1000000001-10000001-1001) and had been moved over from the example.org domain (old SID S-1-5-21- 2000000002-2000000002-20000002-2002) and we would detect a repository owned by bobs old SID, we would now lookup the old SID, find it attached to a user named example.com\Bob, look up Bobs current SID, find it belongs to a user named example.com\Bob and print a confusing error message.
So I dunno. Arguing what we care about (is that exact SID equality between the "owner of the directory" and the "user, which the current process is working on behalf of", or do we care about the equality of the "accounts"?) may be a better way to justify this change, if you ask me.quoted
+static BOOL user_sid_to_user_name(PSID sid, LPSTR *str) +{ + SID_NAME_USE pe_use; + DWORD len_user = 0, len_domain = 0; + BOOL translate_sid_to_user; + + /* returns only FALSE, because the string pointers are NULL*/ + LookupAccountSidA(NULL, sid, NULL, &len_user, NULL, &len_domain, + &pe_use); + /*Alloc needed space of the strings*/ + ALLOC_ARRAY((*str), (size_t)len_domain + (size_t)len_user); + translate_sid_to_user = LookupAccountSidA(NULL, sid, (*str) + len_domain, &len_user, + *str, &len_domain, &pe_use); + if (translate_sid_to_user == FALSE) { + FREE_AND_NULL(*str); + }Style: do not enclose a single-statement block inside {}.quoted
+ else + (*str)[len_domain] = '/'; + return translate_sid_to_user; +}quoted
@@ -2767,7 +2788,9 @@ int is_path_owned_by_current_sid(const char *path, struct strbuf *report) } else if (report) { LPSTR str1, str2, to_free1 = NULL, to_free2 = NULL; - if (ConvertSidToStringSidA(sid, &str1)) + if (user_sid_to_user_name(sid, &str1)) + to_free1 = str1; + else if (ConvertSidToStringSidA(sid, &str1)) to_free1 = str1;Do these two helper functions return pointers pointing into the same kind of memory that you can free with the same function? That is ...quoted
... "'%s' is owned by:\n" "\t'%s'\nbut the current user is:\n" "\t'%s'\n", path, str1, str2); - LocalFree(to_free1); - LocalFree(to_free2); + free(to_free1); + free(to_free2);... the original code seems to say that the piece of memory we obtain from ConvertSidToStringSidA() must not be freed by calling free() but use something special called LocalFree(). I am assuing that your user_sid_to_user_name() returns a regular piece of memory that can be freed by calling regular free()? Do we need to keep track of where we got the memory from and use different function to free each variable, or something (again I do not do Windows so I'll defer all of these to Dscho, who is CC'ed this time). Thanks and a happy new year.quoted
} }