Hi,
On Thu, 14 Dec 2006, Junio C Hamano wrote:
Johannes Schindelin [off-list ref] writes:
quoted
+ ret = show_object(o->sha1, 1);
+ objects[i].item = (struct object *)t->tagged;
+ i--;
+ break;
Good hack ;-).
Tail recursion ;-)
It has a nice side effect, too: the _name_ of the object is not changed,
so if you show a tag which references a tree, you will see the name of the
tag as if it were the name of the tree.
Ciao,
Dscho