On Sun, Feb 21, 2016 at 04:15:31PM -0500, Eric Sunshine wrote:
On Sun, Feb 21, 2016 at 12:32 PM, John Keeping [off-list ref] wrote:
quoted
GNU grep 2.23 detects the input used in this test as binary data so it
does not work for extracting lines from a file. We could add the "-a"
option to force grep to treat the input as text, but not all
implementations support that. Instead, use sed to extract the desired
lines since it will always treat its input as text.
Signed-off-by: John Keeping <redacted>
---
diff --git a/t/t9200-git-cvsexportcommit.sh b/t/t9200-git-cvsexportcommit.sh
@@ -35,7 +35,7 @@ exit 1
check_entries () {
# $1 == directory, $2 == expected
- grep '^/' "$1/CVS/Entries" | sort | cut -d/ -f2,3,5 >actual
+ sed -ne '\!^/!p' "$1/CVS/Entries" | sort | cut -d/ -f2,3,5 >actual
This works with BSD sed, but double negatives are confusing. Have you
considered this instead?
sed -ne '/^\//p' ...
What do you mean double negatives? Do you mean using "!" as an
alternative delimiter? I find changing delimters is normally simpler
than following multiple levels of quoting for escaping slashes, although
in this case it's simple enough that it doesn't make much difference.