Re: [PATCH 1/3] cache-tree: Create/update cache-tree on checkout
From: Junio C Hamano <hidden>
Date: 2016-06-15 23:01:46
David Turner [off-list ref] writes:
quoted hunk
When git checkout checks out a branch, create or update the cache-tree so that subsequent operations are faster. Signed-off-by: David Turner <redacted> --- builtin/checkout.c | 4 ++++ cache-tree.c | 22 ++++++++++++---------- cache-tree.h | 1 + t/t0090-cache-tree.sh | 15 ++++++++++++++- 4 files changed, 31 insertions(+), 11 deletions(-)diff --git a/builtin/checkout.c b/builtin/checkout.c index 07cf555..df791e8 100644 --- a/builtin/checkout.c +++ b/builtin/checkout.c@@ -553,6 +553,10 @@ static int merge_working_tree(const struct checkout_opts *opts, } } + if (write_cache_as_tree(NULL, WRITE_TREE_DO_NOT_WRITE, "")) { + warn("Unable to write cache_tree"); + } +
This is not even warn-worthy event, isn't it? "checkout -m other" would attempt a three-way merge to replay your local changes relative to your current HEAD in the context of "other" branch and will leave conflicts in the index and in the working tree, and it is perfectly a normal thing that you cannot write the index in such a state as a tree object. Perhaps you should check if the index is unmerged before even attempting to compute the cache tree. Also it looks very strange that write-cache-as-tree, whose *PRIMARY* function is to write a tree, receives a "DO NOT WRITE" option here. I understand that you want a new interface into the cache-tree subsystem that only updates the cache-tree but it somehow smells like a sloppy/lazy refactoring that is not done quite right.