Thread (1 message) 1 message, 1 author, 2016-06-15

Re: t1450-fsck (sometimes/often) failes on Mac OS X

From: Junio C Hamano <hidden>
Date: 2016-06-15 22:54:55

Torsten Bögershausen [off-list ref] writes:
quoted hunk
With help of Junio's comments I probably found the reason why the test
behaves differently:

The objects are checked in a certain order, based on the inode number.

Which seems to be the same on most machines: when files are created
in a certain order, then the inode numbers are in the same order.

When the inode numbering changes for reasons known to the file system,
the order changes and fsck takes a different code path.

To provoke the error, the following helped at my Linux box:
diff --git a/builtin/fsck.c b/builtin/fsck.c
index a710227..bba8082 100644
--- a/builtin/fsck.c
+++ b/builtin/fsck.c
@@ -373,7 +373,7 @@ static struct {

 static int ino_compare(const void *_a, const void *_b)
 {
-       const struct sha1_entry *a = _a, *b = _b;
+       const struct sha1_entry *a = _b, *b = _a;
        unsigned long ino1 = a->ino, ino2 = b->ino;
        return ino1 < ino2 ? -1 : ino1 > ino2 ? 1 : 0;
 }
The bad news: I haven't found the time to prepare a fix.
Thanks for a reproduction. Yes, the test t1450.13 is expecting too
much.

If it finds the $sha blob first and then looks at $tag tag, then it
will notice that the tag is pointing at a blob but claims it must be
a commit.  If it finds the $tag tag first, it will remember that the
tag claimed $sha must be a commit, and when later it sees $sha, it
finds that it is not of the type it is expecting (namely, a commit),
and says "the object called $sha is broken".

So "test_must_fail git fsck --tags" is correct.  The fsck must find
the breakage either way.

The last piece to expect "error in tag.*broken links" in the output
is wrong.  Probably we should remove the misguided check and end
it with "test_must_fail git fsck --tags".
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