Re: git checkout creates strange '(null)'-branch

Johannes Sixt [off-list ref] writes:

Am 5/8/2012 13:24, schrieb Erik Faye-Lund:

quoted

+		git show-ref | !grep "(null)"

...

quoted

Now, doing this doesn't make my test above pass,

It is unlikely to pass if you used this test script literally, because

   $ !grep
   !grep: command not found

"!" is not an operator in a shell script. Insert a space.

Good eyes.  Also wouldn't it be a bit pointless to grep for (null) in the
first place?  It comes only because a particular implementation of
vsnprintf() happens to emit it when asked to turn a NULL pointer into a
string, and on other platforms it is allowed to segfault.