Thread (8 messages) flat view 8 messages, 6 authors, 2016-06-15

Re: [PATCH] completion: fix issue with process substitution not working on Git for Windows

From: Johannes Sixt <hidden>
Date: 2016-06-15 22:52:19

Am 25.10.2011 20:01, schrieb Stefan Naewe:
quoted hunk ↗ jump to hunk
Git for Windows comes with a bash that doesn't support process substitution.
It issues the following error when using git-completion.bash with
GIT_PS1_SHOWUPSTREAM set:

$ export GIT_PS1_SHOWUPSTREAM=1
sh.exe": cannot make pipe for process substitution: Function not implemented
sh.exe": cannot make pipe for process substitution: Function not implemented
sh.exe": <(git config -z --get-regexp '^(svn-remote\..*\.url|bash\.showupstream)$' 2>/dev/null | tr '\0\n' '\n '): ambiguous redirect

Replace the process substitution with a simple "echo $var | while...".

Signed-off-by: Stefan Naewe <redacted>
---
 contrib/completion/git-completion.bash |    4 +++-
 1 files changed, 3 insertions(+), 1 deletions(-)
diff --git a/contrib/completion/git-completion.bash b/contrib/completion/git-completion.bash
index 8648a36..926db80 100755
--- a/contrib/completion/git-completion.bash
+++ b/contrib/completion/git-completion.bash
@@ -110,6 +110,8 @@ __git_ps1_show_upstream ()
 	local upstream=git legacy="" verbose=""
 
 	# get some config options from git-config
+	output="$(git config -z --get-regexp '^(svn-remote\..*\.url|bash\.showupstream)$' 2>/dev/null | tr '\0\n' '\n ')"
+	echo "$output" | \
 	while read key value; do
 		case "$key" in
 		bash.showupstream)
@@ -125,7 +127,7 @@ __git_ps1_show_upstream ()
 			upstream=svn+git # default upstream is SVN if available, else git
 			;;
 		esac
-	done < <(git config -z --get-regexp '^(svn-remote\..*\.url|bash\.showupstream)$' 2>/dev/null | tr '\0\n' '\n ')
+	done
 
 	# parse configuration values
 	for option in ${GIT_PS1_SHOWUPSTREAM}; do
Are you sure that the result still works as intended? The while loop
sets a few variables. When you place it in a pipe, the loop runs in a
subshell, and subsequent code will not see the modified values. Unless
bash knows how to optimize away the subshell, that is.

OTOH, when you use while ...; do ...; done < <(...), the while loop is
not in a subshell.

An alternative is to use:  while ...; do ...; done <<< "$output"

BTW, you don't need to protect the end-of-line with a backslash if the
line ends with the pipe symbol.

-- Hannes
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