Re: [PATCH 2/2] Ensure git ls-tree exits with a non-zero exit code if read_tree_recursive fails.

In the case of a corrupt repository, git ls-tree may report an error but
presently it exits with a code of 0.

This change uses the return code of read_tree_recursive instead.

Improved-by: Jens Lehmann [off-list ref]
Signed-off-by: Jon Seymour <redacted>
---
 builtin/ls-tree.c               |    6 +++---
 t/t3103-ls-tree-missing-tree.sh |    2 +-
 2 files changed, 4 insertions(+), 4 deletions(-)

diff --git a/builtin/ls-tree.c b/builtin/ls-tree.c
index f08c5b0..6d6c992 100644
--- a/builtin/ls-tree.c
+++ b/builtin/ls-tree.c

@@ -120,7 +120,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
 {
 	unsigned char sha1[20];
 	struct tree *tree;
-	int i, full_tree = 0;
+	int i, full_tree = 0, err;
 	const struct option ls_tree_options[] = {
 		OPT_BIT('d', NULL, &ls_options, "only show trees",
 			LS_TREE_ONLY),

@@ -173,7 +173,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
 	tree = parse_tree_indirect(sha1);
 	if (!tree)
 		die("not a tree object");
-	read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
+	err = read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
 
-	return 0;
+	return err;
 }