Re: [RFC] notes: avoid recommitting identical trees

On Tue, Aug 31, 2010 at 08:26:34PM +0200, Michael J Gruber wrote:

Junio C Hamano venit, vidit, dixit 31.08.2010 18:44:

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Michael J Gruber [off-list ref] writes:

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+	if (!parent || parse_commit(parent->item) || parse_tree(parent->item->tree) ||
+		hashcmp(parent->item->tree->object.sha1, tree_sha1)) {

I didn't check, but I can imagine you can drop the parse_tree here. We
should know the object sha1 once the commit is parsed.

parse_commit() does a lookup_tree() but I don't think that it parses the
tree, i.e. I don't hink it fills in tree->object.sha1.

Huh?  parse_tree(tree) calls read_sha1_file(tree->object.sha1) to parse
the tree.  How can it do without filling tree->object.sha1?

Sure parse_tree() does that. That's why I call it. I never claimed it
doesn't.

I think the claim is that it is already parsed. Look at parse_tree. The
first non-declaration lines are:

  if (item->object.parsed)
          return 0;
  buffer = read_sha1_file(item->object.sha1, &type, &size);

So _somebody_ has already filled in item->object.sha1.

-Peff