Re: Find successor of common ancestor
From: Enrico Weigelt <hidden>
Date: 2016-06-15 22:49:08
* Johan Herland [off-list ref] wrote:
IINM you have the following situation A0---A1---A2---A3---A4 <-- A' \ B1---B2---B3--B4 <-- B' ...and you want to rebase B' (i.e. B1 through B4), first onto A1, then onto A2, the onto A3, and finally onto A4. I have no idea WHY you would want to do this (rebasing directly onto A4 (like Santi suggests) is much cheaper), but you can certainly coax Git into doing it, anyway.
If the branches go off too far, you can easily end up in a lot of unresolvable conflicts, while on zip-rebase, there's great chance that 3way-merge will catch this.
To list commits A1, A2, A3, A4 (in that order), do:
git rev-list --reverse B'..A'
You can now loop over the results like this:
git checkout B'
for a in $(git rev-list --reverse ..A'); do
git rebase $a
doneThx, I'll have a try :) cu -- ---------------------------------------------------------------------- Enrico Weigelt, metux IT service -- http://www.metux.de/ phone: +49 36207 519931 email: weigelt@metux.de mobile: +49 151 27565287 icq: 210169427 skype: nekrad666 ---------------------------------------------------------------------- Embedded-Linux / Portierung / Opensource-QM / Verteilte Systeme ----------------------------------------------------------------------