Re: [PATCH] bash: offer only paths after '--'

SZEDER Gábor [off-list ref] writes:

On Tue, Jul 08, 2008 at 11:18:37PM +0000, Shawn O. Pearce wrote:

quoted

Junio C Hamano [off-list ref] wrote:

quoted

SZEDER Gábor [off-list ref] writes:

quoted

+		c=$((++c))

This assignment is somewhat curious, although it should work as expected
either way ;-)

...
Maybe an old C++ "heritage"?  In C++ it matters for class types (e.g.
iterators), because the postfix operator might be slower than the
prefix.

Heh, I was not talking about prefix vs postfix but about the assignment
into the variable that is incremented as a side effect of evaluating the
left hand side.  If you know the variable is incremented already there is
no point in assigning the resulting value to it ;-)

	c=$(( $c + 1 ))

would have avoided such an uneasy feeling, and would have been more
portable.  Even though $((x)) and $(($x)) are supposed to evaluate the
same, some shells do not like dollar-less variable names in arithmetic
expansion, and prefix/postfix increment/decrement are not required to be
supported by POSIX.

But this script being bash completion, we can use as much bashism as we
want here; perhaps I would have written:

	: $((c++))