Re: why is git destructive by default? (i suggest it not be!)

To re-ask the same question I asked in my last post, using your ascii
pictures...


Let's assume we're here..

.<---.<---.<---A<---X<---Y    <--- master
\
\--B<---C    <--- customer_A_branch <=== HEAD


And this person and everyone else moves their head pointers back to master
without merging:


.<---.<---.<---A<---X<---Y    <--- master              <=== HEAD
\
\--B<---C    <--- customer_A_branch


Now, five years down the road, our tree looks like:


.<---A<---X<---Y<---.<--.<--.(3 years of changes)<---ZZZ<--- master  <=== HEAD
\
\--B<---C   <--- customer_A_branch

And someone does:

git-branch -f customer_A_branch ZZZ

To bring us to:

.<---A<---X<---Y<---.<--.(3 years of changes)<---ZZZ<--- master  <=== HEAD
\                                           \
\--B<---C                                   \-- customer_A_branch


..at this point, will a GC keep "B<--C", or garbage collect the commits and
throw them away?