Re: Distribution of longest common hash prefixes
From: Randal L. Schwartz <hidden>
Date: 2016-06-15 22:43:02
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"Randal" == Randal L Schwartz [off-list ref] writes:
Randal> git-rev-list --objects HEAD | sort | perl -lne '
Randal> substr($_, 40) = "";
Randal> if (defined $p) {
Randal> ($p ^ $_) =~ /^(\0*)/;
Randal> $common = length $1;
Randal> if (defined $pcommon) {
Randal> $count[$pcommon > $common ? $pcommon : $common]++;
Randal> }
Randal> }
Randal> $p = $_;
Randal> $pcommon = $common;
Randal> END { print "$_: $count[$_]" for 0..$#count }
Randal> '
And that's off by one on either end. :)
git-rev-list --objects HEAD | sort | perl -lne '
substr($_, 40) = "";
if (defined $p) {
($p ^ $_) =~ /^(\0*)/;
$common = length $1;
if (defined $pcommon) {
$count[$pcommon > $common ? $pcommon : $common]++;
} else {
$count[$common]++; # first item
}
}
$p = $_;
$pcommon = $common;
END {
$count[$common]++; # last item
print "$_: $count[$_]" for 0..$#count;
}
'
Which now yields:
0:
1:
2: 6
3: 21155
4: 15008
5: 1232
6: 90
7:
8: 2
And *that* totals to 37493, which is the number of objects. Yeay.
--
Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095
[off-list ref] <URL:http://www.stonehenge.com/merlyn/>
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