Re: Bug in qeth in 2.6

Hi,

sorry, I still don't see it...

2.4 was like this:

           result = 0;
           for (all in list) {
                       if (something)
                                   result = QETH_VERIFY_IS_SOMETHING;

and it stops here if something...

           }

... and here follows a second loop over the list, looking for foo().

2.6 is:

           result = 0;
           for (all in list) {
                       result = (something)? QETH_VERIFY_IS_SOMETHING:

foo();

and here it stops if something or foo()...

           }

...no second loop here.

Since it's either something or foo(), this looks like the same behaviour to
me.

Best regards / Mit freundlichen Gruessen

Cornelia Huck
zLinux Developer
Tel.: +49-7031-16-4837, Mail: cohuck@de.ibm.com