We're experiencing some unexpected behavior with binary generated with
the said version of gcc; namely that variables declared to char appear
to be defaulting to unsigned char.
#include <stdio.h>
#include <stdlib.h>
int main( int argc, char** args, char** envs )
{
char sc;
unsigned char uc;
sc = uc = -3;
printf( "signed char: %d unsigned char: %d\n", sc, uc );
if ( sc > (char)0 )
printf( "sc is greater than zero\n" );
else
printf( "sc is less or equal to zero\n" );
return 0;
}
The preceeding code would produce the following unexpected result --
signed char: 253 unsigned char: 253
sc is greater than zero
Making the following change --
signed char sc;
unsigned char uc;
.
.
Would produce the expected result --
signed char: -3 unsigned char: 253
sc is less or equal to zero
Can someone shed some light on this? (As in, is this "normal" and we do
not know only because we've been living under a rock ;-)
** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/
On Wed, 2003-12-17 at 17:02, David C. Chiu wrote:
We're experiencing some unexpected behavior with binary generated with
the said version of gcc; namely that variables declared to char appear
to be defaulting to unsigned char.
#include <stdio.h>
#include <stdlib.h>
int main( int argc, char** args, char** envs )
{
char sc;
unsigned char uc;
sc = uc = -3;
printf( "signed char: %d unsigned char: %d\n", sc, uc );
if ( sc > (char)0 )
printf( "sc is greater than zero\n" );
else
printf( "sc is less or equal to zero\n" );
return 0;
}
The preceeding code would produce the following unexpected result --
signed char: 253 unsigned char: 253
sc is greater than zero
Making the following change --
signed char sc;
unsigned char uc;
.
.
Would produce the expected result --
signed char: -3 unsigned char: 253
sc is less or equal to zero
Can someone shed some light on this? (As in, is this "normal" and we do
not know only because we've been living under a rock ;-)
This behavior is indeed "normal". For some reason (compatibility with
AIX, I think) the gcc compiler for ppc has always made char unsigned by
default.
Try adding the -fsigned-char option to you gcc command line.
--Guy
** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/
On Wed, 17 Dec 2003, David C. Chiu wrote:
We're experiencing some unexpected behavior with binary generated with
the said version of gcc; namely that variables declared to char appear
to be defaulting to unsigned char.
[ snip ]
Can someone shed some light on this? (As in, is this "normal" and we do
not know only because we've been living under a rock ;-)
It is allowable by the specification. C89 allowed char to be either
signed or unsigned, it was up to the implementation to decide which.
-Bret
--
Bret Indrelee QLogic Corporation
Bret.Indrelee@qlogic.com 6321 Bury Drive, St 13, Eden Prairie, MN 55346
** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/