x86 boot gdt

Hello all,

Have a little question about gdt initialization. We can see the following:

[GDT_ENTRY_BOOT_CS] = GDT_ENTRY(0xc09b, 0, 0xfffff),

in the arch/x86/boot/pm.c. Why accessed bit is set here (9b)? I see
that it was not set (9a) in the earliest versions. What's reason was
to change it?

-- 
_________________________
0xAX