Re: [PATCH/RFC] avoid accessing _all_ loose refs in git-show-ref
From: Junio C Hamano <hidden>
Date: 2016-08-11 19:32:33
Johannes Schindelin [off-list ref] writes:
This is kind of quick and dirty.
Maybe I am blind, but why don't you just do a resolve_ref() regardless of packedness? It only builds the packed refs list when it is not found as a loose ref, and never builds the loose refs list. You probably would want to reject the ones that says REF_ISSYMREF.
An alternative would be to pack the tags _per default_. I once argued for that, but it appears nobody liked that idea. I even proposed to pack _all_ refs, and I still think this would be a good idea.
I do not think packing all refs is such a good idea. Branches are meant to be worked on and extended so the packed ones would become stale quickly. Packing all tags by default is something we would want when everybody knows how to handle them.
Isn't it a bug that --verify succeeds, if only _one_ ref passed to the command exists?
I think --verify should insist a single parameter, just like
rev-parse.
So wouldn't the code be like:
if (verify) {
int flag;
if (pattern[1])
die("Eh?");
if (resolve_ref(pattern[0], sha1, 1, &flag) &&
(flag & REF_ISSYMREF) == 0) {
printf("%s %s\n",
sha1_to_hex(sha1), pattern[0]);
exit(0);
} else
die("no match");
}
???