Jeff King [off-list ref] writes:
When pack-objects collects the list of objects to pack
(either from stdin, or via its internal rev-list), it
filters each one through want_object_in_pack().
This function loops through each existing packfile, looking
for the object. When we find it, we mark the pack/offset
combo for later use. However, we can't just return "yes, we
want it" at that point. If --honor-pack-keep is in effect,
we must keep looking to find it in _all_ packs, to make sure
none of them has a .keep. Likewise, if --local is in effect,
we must make sure it is not present in any local pack.
s/any local pack/any non-local pack/, no?
quoted hunk
diff --git a/builtin/pack-objects.c b/builtin/pack-objects.c
index a2f8cfd..55ef5a8 100644
--- a/builtin/pack-objects.c
+++ b/builtin/pack-objects.c
@@ -981,6 +981,8 @@ static int want_object_in_pack(const unsigned char *sha1,
return 0;
if (ignore_packed_keep && p->pack_local && p->pack_keep)
return 0;
+ if (!ignore_packed_keep && !local)
+ break;
}
}
OK, so in this loop, we may return "false" (meaning, we do not want
to pack the object) if "local" (do not pack objects that appear in
non-local packs) or "ignore_packed_keep" (do not pack objects that
appear in locally kept packs) are in effect, but if neither of the
options is set, we know that one of the preconditions ("local" or
"ignore_packed_keep") for these two "reject by returning false" if
statements would never trigger for any pack on packed_git list, so
it is safe to break out and return the one that we have found.
If that is what is going on, I would have expected to see this early
break before these "we found that this is available in borrowed pack
and we are only packing local" and "we ignore objects in locally
kept packs" checks return false.
Or am I not following the logic in the loop correctly?
On Mon, Jul 25, 2016 at 12:56:23PM -0700, Junio C Hamano wrote:
quoted
This function loops through each existing packfile, looking
for the object. When we find it, we mark the pack/offset
combo for later use. However, we can't just return "yes, we
want it" at that point. If --honor-pack-keep is in effect,
we must keep looking to find it in _all_ packs, to make sure
none of them has a .keep. Likewise, if --local is in effect,
we must make sure it is not present in any local pack.
s/any local pack/any non-local pack/, no?
Oops, yeah.
quoted
diff --git a/builtin/pack-objects.c b/builtin/pack-objects.c
index a2f8cfd..55ef5a8 100644
--- a/builtin/pack-objects.c
+++ b/builtin/pack-objects.c
@@ -981,6 +981,8 @@ static int want_object_in_pack(const unsigned char *sha1,
return 0;
if (ignore_packed_keep && p->pack_local && p->pack_keep)
return 0;
+ if (!ignore_packed_keep && !local)
+ break;
}
}
OK, so in this loop, we may return "false" (meaning, we do not want
to pack the object) if "local" (do not pack objects that appear in
non-local packs) or "ignore_packed_keep" (do not pack objects that
appear in locally kept packs) are in effect, but if neither of the
options is set, we know that one of the preconditions ("local" or
"ignore_packed_keep") for these two "reject by returning false" if
statements would never trigger for any pack on packed_git list, so
it is safe to break out and return the one that we have found.
Correct.
If that is what is going on, I would have expected to see this early
break before these "we found that this is available in borrowed pack
and we are only packing local" and "we ignore objects in locally
kept packs" checks return false.
Or am I not following the logic in the loop correctly?
Yeah, I think that would work. It has to come after "did we find this in
the pack", obviously. And it has to come after the other unrelated
checks ("are we just finding it to exclude?" and "are we
incremental?"). But you could do:
if (!*found_pack) {
... first find! fill in found pack, etc ...
}
if (exclude)
return 1;
if (incremental)
return 0;
if (!ignore_packed_keep && !local)
break; /* effectively return 1, but I think the break is more clear */
if (local && !p->pack_local)
return 0;
if (ignore_packed_keep && p->pack_local && p->pack_keep)
return 0;
which just bumps it up. I don't think there is a way to make it more
elegant, e.g., by only checking ignore_packed_keep once, because we have
to distinguish between each condition being set independently, or the
case where neither is set.
So I stuck the new check at the end, because to me logically it was "can
we break out of the loop instead of looking at p->next". But I agree it
would be equivalent to place it before the related checks, and I don't
mind doing that if you think it's more readable.
-Peff