Re: [BUG] two-way read-tree can write null sha1s into index

2 messages, 2 authors, 2016-06-15 · open the first message on its own page

Re: [BUG] two-way read-tree can write null sha1s into index

From: Junio C Hamano <hidden>
Date: 2016-06-15 22:55:38

Jeff King [off-list ref] writes:
So I think we need to update twoway_merge to recognize unmerged entries,
which gives us two options:

  1. Reject the merge.

  2. Throw away the current unmerged entry in favor of the "new" entry
     (when old and new are the same, of course; otherwise we would
     reject).

I think (2) is the right thing.
As "--reset" in "read-tree --reset -u A B" is a way to say "we know
we are based on A and we want to go to B no matter what", I agree we
should not reject the merge.

With -m instead of --reset, I am not sure what the right semantics
should be, though.

Re: [BUG] two-way read-tree can write null sha1s into index

From: Jeff King <hidden>
Date: 2016-06-15 22:55:38

On Tue, Jan 01, 2013 at 02:24:46PM -0800, Junio C Hamano wrote:
Jeff King [off-list ref] writes:
quoted
So I think we need to update twoway_merge to recognize unmerged entries,
which gives us two options:

  1. Reject the merge.

  2. Throw away the current unmerged entry in favor of the "new" entry
     (when old and new are the same, of course; otherwise we would
     reject).

I think (2) is the right thing.
As "--reset" in "read-tree --reset -u A B" is a way to say "we know
we are based on A and we want to go to B no matter what", I agree we
should not reject the merge.

With -m instead of --reset, I am not sure what the right semantics
should be, though.
Good point; I was just thinking about the --reset case.

With "-m", though, we could in theory carry over the unmerged entries
(again, assuming that "old" and "new" are the same; otherwise it is an
obvious reject). But those entries would be confused with any new
unmerged entries we create. It seems we already protect against this,
though: "read-tree -m" will not run at all if you have unmerged entries.

Likewise, "checkout" seems to have similar protections.

So I think it may be a non-issue.

-Peff
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