[Buildroot] [/bin/sh which ar] should be [/bin/sh -c "which ar"]
From: Ulf Samuelsson <hidden>
Date: 2007-07-08 04:35:39
When the host tools are determined in the top Makefile (every time make us run) this fails 5 times with the error message: /usr/bin/which: /usr/bin/which: cannot execute binary file What happens inside the Makefile is that a command is run: $ /bin/sh which ar and the bash shell does not like this on my OpenSuSE 10.2 system $ /bin/sh -c "which ar" will do what we want, so I would like to apply the following patch Any comments? Index: Makefile ===================================================================
--- Makefile (revision 19026)
+++ Makefile (arbetskopia)@@ -78,11 +78,11 @@ ifndef HOSTLD HOSTLD:=ld endif -HOSTAR:=$(shell $(CONFIG_SHELL) which $(HOSTAR) || type -p $(HOSTAR) ||
echo ar) -HOSTAS:=$(shell $(CONFIG_SHELL) which $(HOSTAS) || type -p $(HOSTAS) || echo as) -HOSTCC:=$(shell $(CONFIG_SHELL) which $(HOSTCC) || type -p $(HOSTCC) || echo gcc) -HOSTCXX:=$(shell $(CONFIG_SHELL) which $(HOSTCXX) || type -p $(HOSTCXX) || echo g++) -HOSTLD:=$(shell $(CONFIG_SHELL) which $(HOSTLD) || type -p $(HOSTLD) || echo ld) +HOSTAR :=$(shell $(CONFIG_SHELL) -c "which $(HOSTAR)" || type -p $(HOSTAR) || echo ar) +HOSTAS :=$(shell $(CONFIG_SHELL) -c "which $(HOSTAS)" || type -p $(HOSTAS) || echo as) +HOSTCC :=$(shell $(CONFIG_SHELL) -c "which $(HOSTCC)" || type -p $(HOSTCC) || echo gcc) +HOSTCXX:=$(shell $(CONFIG_SHELL) -c "which $(HOSTCXX)" || type -p $(HOSTCXX) || echo g++) +HOSTLD :=$(shell $(CONFIG_SHELL) -c "which $(HOSTLD)" || type -p $(HOSTLD) || echo ld) ifndef CFLAGS_FOR_BUILD CFLAGS_FOR_BUILD:=-g -O2 endif Best Regards Ulf Samuelsson